Saturday, 24 February 2024

CBSCE- 9 - TEST PAPER




TEST PAPER- 1

1) Attempt all (1 x3= 3)

a) If cosecθ = 13/12, then the value of tanθ is
i) 12/5 ii) 5/12 iii) 5/13 iv) 5/12

b) If tanA = x/y, then cosA is
i) x/√(x²+ y²) ii) y/√(x²+ y²) iii) (x²- y²)/√(x²+ y²) iv)  (x²- y²)/(x²+ y²)

c) secθ= 
i) hypotenuse/base ii) perpendicular/base iii) base/hypotenuse/base iv) none

2) Answer any 2 (2 x2=4)

a) Given A is an acute angle and cosecA=√2, find the value of (2sin²A + 3 cot²A)/(tan²A - cos²A).

b) If cot θ= 15/8, then find the value of (2sin²θ+ 3 cosθ)/(5 sinθ - 3 cos²θ).

c) If sinθ = 12/13, then find tan²θ - sec²θ.


3) If tanθ= p/q, find the value of (p sinθ - q cosθ)/(p sinθ + q cosθ).
Or
If sinx = √3/2 then value of {(2+ 2 sinx)(1- tanx)}/{(1+cotx)(2- 2 cosecx)}.

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